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 Andi47 2009-05-13 08:02

How do I integrate the following functions - I somehow don't see the trick...?

a.) integrate (2x² - 3x - 4) /(3x-5) dx

b.) integrate (4x² - 6x + 2)² * (3x - 5) / 2x³ dx

 Batalov 2009-05-13 08:10

Hmm...
a. Divide, and you will get something like ax+b+c/(3x-5) which will become easy.
b. Probably, the easiest to do the same as a.

 Mr. P-1 2009-05-13 14:09

b: Multiply out the numerator and divide term by term by the denominator. The result will be a sum of +ve and -ve powers of x, plus a constant, which can be integrated term by term.

a. Do the substitution u = 3x - 5 then proceed as above.

 Andi47 2009-05-13 17:49

[QUOTE=Mr. P-1;173419]b: Multiply out the numerator and divide term by term by the denominator. The result will be a sum of +ve and -ve powers of x, plus a constant, which can be integrated term by term.

a. Do the substitution u = 3x - 5 then proceed as above.[/QUOTE]

Thanks! Seems I've been somewhat out of practice... :blush:

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