Exit status 15
While running GMPECM with B1=11000000 and c=1302, it stopped with Exit status 15 and found no factors. The only place I have found the exit status values documented is the Linux Man page for gmpecm at [url]https://www.systutorials.com/docs/linux/man/1gmpecm/[/url]. It doesn't show exit status 15.
Anyone know what this value means? I was running in quiet mode so no other indications. 
[QUOTE=shortcipher;488275]While running GMPECM with B1=11000000 and c=1302, it stopped with Exit status 15 and found no factors. The only place I have found the exit status values documented is the Linux Man page for gmpecm at [url]https://www.systutorials.com/docs/linux/man/1gmpecm/[/url]. It doesn't show exit status 15.
Anyone know what this value means? I was running in quiet mode so no other indications.[/QUOTE] My suspicion is that exit status 15 means 'exit status 15', which means 'the process was terminated'  usually this means the computer ran out of memory and decided to kill ecm. You're right that +15 is not a valid configuration of set bits for a gmpecm status. 
@fivemack was right in saying that the process was terminated. I was running GMPECM on Windows 7 as a Python subprocess. Akos Kiss at [url]https://bugs.python.org/issue31863[/url] reports that processes CAN return exit code 15 when terminated on Windows. In my case, the GMPECM subprocess was terminated by another process running on the same PC which was overzealous in trying to clean up orphaned subprocesses.

Sorry if this is a bit offtopic:
In looping mode using [C]one[/C], would GMPECM produce a nonzero exit code if a factor was found? 
Yes! If it finds the number itself:
[CODE][B]~$[/B] echo 2047  ecm one 1000 GMPECM 7.0.4 [configured with GMP 6.2.0, enableasmredc] [ECM] Input number is 2047 (4 digits) Using B1=1000, B2=51606, polynomial x^1, sigma=1:2307810929 Step 1 took 1ms ********** Factor found in step 1: 2047 Found input number N [B]~$[/B] echo $? 8[/CODE] If it finds a factor and the cofactor is prime (maybe PRP): [CODE][B]~$[/B] echo 2047  ecm one 1 GMPECM 7.0.4 [configured with GMP 6.2.0, enableasmredc] [ECM] Input number is 2047 (4 digits) Using B1=1, B2=12, polynomial x^1, sigma=1:309160743 Step 1 took 0ms Step 2 took 0ms ********** Factor found in step 2: 23 Found prime factor of 2 digits: 23 Prime cofactor 89 has 2 digits [B]~$[/B] echo $? 14[/CODE] If it finds a factor and the cofactor is composite: [CODE][B]~$[/B] echo '2*(2^20471)'  ecm one 1 GMPECM 7.0.4 [configured with GMP 6.2.0, enableasmredc] [ECM] Input number is 2*(2^20471) (617 digits) ********** Factor found in step 1: 2 Found prime factor of 1 digits: 2 Composite cofactor (2*(2^20471))/2 has 617 digits [B]~$[/B] echo $? 6[/CODE] I'd have to look into the code if there are other possibilities. 
[QUOTE=kruoli;559927]Yes! If it finds the number itself:
[CODE][B]~$[/B] echo 2047  ecm one 1000 GMPECM 7.0.4 [configured with GMP 6.2.0, enableasmredc] [ECM] Input number is 2047 (4 digits) Using B1=1000, B2=51606, polynomial x^1, sigma=1:2307810929 Step 1 took 1ms ********** Factor found in step 1: 2047 Found input number N [B]~$[/B] echo $? 8[/CODE]If it finds a factor and the cofactor is prime (maybe PRP): [CODE][B]~$[/B] echo 2047  ecm one 1 GMPECM 7.0.4 [configured with GMP 6.2.0, enableasmredc] [ECM] Input number is 2047 (4 digits) Using B1=1, B2=12, polynomial x^1, sigma=1:309160743 Step 1 took 0ms Step 2 took 0ms ********** Factor found in step 2: 23 Found prime factor of 2 digits: 23 Prime cofactor 89 has 2 digits [B]~$[/B] echo $? 14[/CODE]If it finds a factor and the cofactor is composite: [CODE][B]~$[/B] echo '2*(2^20471)'  ecm one 1 GMPECM 7.0.4 [configured with GMP 6.2.0, enableasmredc] [ECM] Input number is 2*(2^20471) (617 digits) ********** Factor found in step 1: 2 Found prime factor of 1 digits: 2 Composite cofactor (2*(2^20471))/2 has 617 digits [B]~$[/B] echo $? 6[/CODE] I'd have to look into the code if there are other possibilities.[/QUOTE] Interesting. Thank you for the reply. I was looking for a way to incorporate this into a Windows batch file. Below is an example: [QUOTE]echo "2^18611"  ecm c 100 v one 3 1e6 if %errorlevel% neq 0 goto errhandler[/QUOTE]In this case, [U]neq[/U] is "not equal to." Knowing the specific return value is not really necessary. The three examples above demonstrate that [C]one[/C] also works in a nonlooping mode. I was wondering about this. 
All times are UTC. The time now is 14:33. 
Powered by vBulletin® Version 3.8.11
Copyright ©2000  2021, Jelsoft Enterprises Ltd.