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RomanM 2021-08-26 15:01

Inverse of FFT multiplication?
on the sample
101*109=11009 (1)
let x=10
at the same time
Bold polinomial exist for any composite.
So if we find the bold for someone x, we can manage to factor number
Seems still not good and complicated...
Let x=100
and 11009=x^2+10*x+9
100 is lucky number? Yes and no. 100 = 101-1))
ok. Let x=98
...for some x, numbers start breaks to factors)
in this simple form - take some x, make polynomial from given composite number N and try to factor, not numeric but in the algebraic - sometimes yield to results for factor N or N+1 or N-1))
P.S. I have no program for this part of idea.

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