probable dud
((2^18752301)*10^564501+2^18752291) has small factors?
I don't know...:smile: 
Well, have you PRP tested this with PFGW? Or are you asking us to do it for you?

[QUOTE=mathwiz;555531]Or are you asking us to do it for you?[/QUOTE]It wouldn't be much different from Google demanding everyone do their job for them with the captcha images.

[QUOTE=mathwiz;555531]Well, have you PRP tested this with PFGW? Or are you asking us to do it for you?[/QUOTE]
Unfortunally my computer is broken! 
So what makes you think it is a probable prime? :confused:

[QUOTE=enzocreti;555513][B]((2^18752301)*10^564501+2^18752291) [/B]has small factors?[/QUOTE]
This appears to be a request for somebody with a lot of cores to run it. I am not sure [I]PFGW[/I] could handle it in this form. Then again, maybe it could. Any person trying may need several generations of descendants to see it done. It might have to look something like this though: [QUOTE](((2^18752301)*10^564501+2)^18752291)[/QUOTE]I am not sure how [I]PFGW[/I] handles parenthetical's or if it will accept them at all. :no: 
[QUOTE=CRGreathouse;555541]So what makes you think it is a probable prime? :confused:[/QUOTE]
Pg(69660) is prime 69660 is multiple of 215 and congruent to 215 mod 323...it is also 6 mod 13... using wolphram numbers of this form are 69660+xn where x i don't remember what it is. 69660 is the least number N such that N is 215 mod 323, N is 0 mod 215 and N is 6 mod 13... then you have other values using Chinese remainder theorem 
:poke:
:dnftt: 
[QUOTE=enzocreti;555533]Unfortunally my computer is broken![/QUOTE]
so how/where did you somehow come up with this number? 
[QUOTE=enzocreti;555550]Pg(69660) is prime
69660 is multiple of 215 and congruent to 215 mod 323...it is also 6 mod 13... using wolphram numbers of this form are 69660+xn where x i don't remember what it is. 69660 is the least number N such that N is 215 mod 323, N is 0 mod 215 and N is 6 mod 13... then you have other values using Chinese remainder theorem[/QUOTE] I agree that 69660 == chinese([Mod(215,323), Mod(0,215), Mod(6,13)]), and I'm prepared to assume that Pg(69660) is prime. But why should that make us think that ((2^18752301)*10^564501+2^18752291) is likely to be prime? 
[QUOTE=CRGreathouse;555541]So what makes you think it is a probable prime? :confused:[/QUOTE]
Putting this to rest: [CODE]$ ./pfgw64 i V N T8 q"((2^18752301)*10^564501+2^18752291)" PFGW Version 4.0.0.64BIT.20190528.x86_Dev [GWNUM 29.8] Generic modular reduction using generic reduction AVX512 FFT length 384K, Pass1=1K, Pass2=384, clm=1, 8 threads on A 3750464bit number Resuming at bit 1480000 ((2^18752301)*1....501+2^18752291) is composite: RES64: [52E573162A497910] (5201.6106s+0.0149s)[/CODE] As to whether the factors are small, I have neither the time nor interest to care. 
... ... Easily sniped.

[QUOTE=mathwiz;555571]Putting this to rest:
[CODE]$ ./pfgw64 i V N T8 q"((2^18752301)*10^564501+2^18752291)" [/QUOTE] The problem with doing this is that it achieves the opposite of your hope rather than show the OP that his ideas are bunk and shouldn't be written out in public, it teaches him that if he asks a dumb enough question, someone will do the calculation work for him to show it's dumb. What he wants is someone to do the computing, and you did his bidding. We prefer you didn't. It's cool to post the command you would use (as you also did), so that OP could do it himself if he wasn't so lazy. 
[COLOR="Red"]MOD NOTE: next cry of "Fire!" in a cinema theater will be punished by a detention.[/COLOR]
People do come to this forum to find news of a, say, next Mersenne prime (which are now prescreened as PRPs), so the next person who will call their thread "[I]Probable prime[/I]" and when asked for reasons why that did such a thing would show a patty cake made out of #2, will get that cake on their face and a two week banishment as well. Call it something else, like "I made up a number", or "asking for an advice" or "I don't know how to check this", or whatever. 
...but this is almost surely PRP!
(2^36808001)*10^1108031+2^36807991

...not that's not prp
how about this:
(2^14301361)*10^430514+2^14301351??? I made a stupid mistacke the candidates have the form pg(69660+1360476n) because 69660 is the least N congruent to 215 mod 323 and 0 mod 324 and 6 mod 13 
[QUOTE=enzocreti;555614] ...but this is almost surely PRP!
(2^36808001)*10^1108031+2^36807991[/QUOTE] Divisible by 71. [QUOTE=enzocreti;555615]how about this: (2^14301361)*10^430514+2^14301351[/QUOTE] Divisible by 14437. [QUOTE=enzocreti;555615]how about this: I made a stupid mistacke [/QUOTE] Correct. How about a 2 weeks ban? 
[QUOTE=Batalov;555616]Divisible by 71.
Divisible by 14437. Correct. How about a 2 weeks ban?[/QUOTE] You beat me to it! :jail: 
...i did not...
i did not take into account that N must be 10^m mod 41
let's guess congruent to 1 mod 41 so the candidates must have the form pg(69660+11992595940n) impossible to test! 
[QUOTE=enzocreti;555619]i did not take into account that N must be 10^m mod 41
let's guess congruent to 1 mod 41[/QUOTE] Do. Not. Guess. There are no guesses in math. log[SUB]10[/SUB]2 is irrational and just [I]happens to be[/I] locally close to 0.3 and that is the only reason that there is some local periodicity of modulos w.r.t. n. This periodicity doesn't hold for larger values of n, so simply stop posting guesses pulled out of your ear [SPOILER](or, as some less polite folks would say, rear)[/SPOILER]. 
[QUOTE=mathwiz;555571]Putting this to rest:
[CODE]$ ./pfgw64 i V N T8 q"((2^18752301)*10^564501+2^18752291)" PFGW Version 4.0.0.64BIT.20190528.x86_Dev [GWNUM 29.8] Generic modular reduction using generic reduction AVX512 FFT length 384K, Pass1=1K, Pass2=384, clm=1, 8 threads on A 3750464bit number Resuming at bit 1480000 ((2^18752301)*1....501+2^18752291) is composite: RES64: [52E573162A497910] (5201.6106s+0.0149s)[/CODE]As to whether the factors are small, I have neither the time nor interest to care.[/QUOTE] I have very little interest. These appear to be something simply pulled out of the air. I tried several formats with PFGW. None worked. I did not try the one above. I do not see the point of doing so. End of line... 
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